These are principles and not a recipe or a plan. Use these to form a problem-solving
plan. (Problem solving itself is a problem…).
The principles are very well explained in Pólya’s light book, How to Solve It. He
later goes into much depth in his two part series on Mathematics and Plausable
Reasoning (volume 1, volume 2).
Check your results somehow, possibly by varying the problem a little.
Trying a different solution technique also can check your problem.
Re-trying the same technique often does not help. People often make
the same mistakes.
Try to generalize a little.
Interpret your results by writing sentences. Often provides a check in itself, or
leads to an alternate route.
Common in mathematics: First publication of a result is long and
hairy. Interested people being interpreting it, and a short or more
direct proof is found.
How many ways can you form 21 cents from dimes, nickles, andpennies?
While thinking of the problem, note that the last 1 cent does not change the number
of ways to form the total. There always will be one penny involved. We should just
drop that one penny.
Plan: Form a table. Then the plan becomes how to form the table.
We can start with an extreme solution and modifiy it one row at a time. In
the table, we push change from left (higher) to right, while checking the
total.
# dimes
# nickles
# pennies
total cents = 20
2
2*10 = 20
1
2
10+2*5 = 20
1
1
5
10+5+5*1 = 20
1
10
10+10*1 = 20
4
4*5 = 20
3
5
3*5+5*1 = 20
2
10
2*5+10*1 = 20
1
15
1*5+15*1 = 20
20
20*1 = 1
So there are nine ways of forming 21 cents from dimes, nickles, and quarters.
Complete the following triangle such that the numbers in the vertices are equal to the
sum of the variables adjacent to them. Assume all the variables are positive
integers.
16
a
b
11
c
15
When considering the problem, look for relationships that can guide your
guesses.
Because a,
b,
and c
are positive, we know the sum of any two is greater than either. That is,
16 = a + b > a,
and 16 = a + b > b.
The initial plan becomes to pick numbers less than the ones shown.
Try a guess, and notice that you only need to pick one number. The rest
are completely determined.
So you can start with a
and guess from numbers less than 11.
16
6
10
11
5
15
Now look back and consider some new relationships:
16 + 11 + 15 = 2(6 + 5 + 10).
Try other numbers in the vertices, see if this relationship holds.
For which numbers does this problem have a solution when
a,
b, and
c
all are positive integers?
Rob goes to the racetrack on a weekly basis. One week he tripled
his money but then lost $12. Returning to the track the next week
with all his money, he doubled his money but then lost $40. Again
he returned to the track with his money. He quadrupled his money
and lost nothing, taking home $224.
How much money did take on his first week above?
First, rephrase the problem mathematically. Let
{M}_{n} be his total
starting in week n.
We want {M}_{1}.
From the problem,
Groups are fine, turn in your own work. Homework is due in or before class on
Mondays.
Exercises for 1.3
Understanding the problem: Problem 6
Guessing and checking: problem 12
Listing: problems 31, 35
Dependencies and diagramming: 28, 57
Note that you may email homework. However, I don’t use MicrosoftTM products
(e.g. Word), and software packages are notoriously finicky about translating
mathematics.
If you’re typing it (which I advise just for practice in whatever tools you use), you
likely want to turn in a printout. If you do want to email your submission, please
produce a PDF or PostScript document.